如何编写laravel中基于join关联查询的代码示例？

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使用 Laravel 进行 JOIN 查询，关联两表：

php$fbainventoryTb=(new App\Model\Amz\Fba\InventoryReport)->getTable();$productTb=(new App\Model\Amz\Product)->getTable();$twinventoryTb=(new App\Model\TWUsa\TwusaInventory)->getTable();$qry=DB::select(SELECT * FROM $fbainventoryTb JOIN $productTb ON $fbainventoryTb.product_id=$productTb.id JOIN $twinventoryTb ON $fbainventoryTb.product_id=$twinventoryTb.product_id);

laravel join关联查询

1、两表关联

$fbaInventoryTb = (new \App\Model\Amz\Fba\InventoryReport)->getTable(); $productTb = (new \App\Model\Amz\Product)->getTable(); $twInventoryTb = (new \App\Model\TWUsa\TwusaInventory)->getTable(); $qry = \DB::table($fbaInventoryTb); $qry->select($fbaInventoryTb.'.*') ->where($fbaInventoryTb.'.ec_id',1) ->leftjoin($productTb, $productTb.'.sku', '=', $fbaInventoryTb.'.sku') ->addSelect($productTb.'.id as goods_id',$productTb.'.sku as mfn', $productTb.'.ec_id as pro_ec_id'); // ->where($productTb.'.ec_id',1); //不应该在此处排除 product 表的ec_id // return $qry->toSql(); $res = $qry->get()->whereIn('pro_ec_id',[1, null] );//leftJion 最后排除不符合条件的

2、三表关联

$qry = \DB::table($twInventoryTb); $qry->select($twInventoryTb.'.*') ->leftjoin($fbaInventoryTb, $fbaInventoryTb.'.fnsku', '=', $twInventoryTb.'.product_sn') ->addSelect($fbaInventoryTb.'.ec_id') ->where($fbaInventoryTb.'.ec_id',1); $qry->LeftJoin($productTb, $productTb.'.sku', '=', $fbaInventoryTb.'.sku') // ->where($productTb.'.ec_id',1) ->addSelect($productTb.'.id as goods_id', $productTb.'.sku as mfn', $productTb.'.ec_id as pro_ec_id'); $res = $qry->get()->whereIn('pro_ec_id', [1, null]);

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