如何使用php的similar_text函数准确比较两个字符串的相似度？

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使用PHP的`similar_text`函数比较字符串相似度，代码如下：

php$word2compare=stupid;$words=array('stupid', 'stu and pid', 'hello', 'foobar', 'stpid', 'upid', 'stuuupid', 'sstuuupiiid');

foreach ($words as $id=> $str) { $similarity=similar_text($word2compare, $str); echo 相似度：{$similarity}\n;}

通过php的 similar_text函数比较两个字符串的相似性

$word2compare = "stupid"; $words = array( 'stupid', 'stu and pid', 'hello', 'foobar', 'stpid', 'upid', 'stuuupid', 'sstuuupiiid', ); while(list($id, $str) = each($words)){ similar_text($str, $word2compare, $percent); print "Comparing '$word2compare' with '$str': "; print round($percent) . "%\n"; } /* Results: Comparing 'stupid' with 'stupid': 100% Comparing 'stupid' with 'stu and pid': 71% Comparing 'stupid' with 'hello': 0% Comparing 'stupid' with 'foobar': 0% Comparing 'stupid' with 'stpid': 91% Comparing 'stupid' with 'upid': 80% Comparing 'stupid' with 'stuuupid': 86% Comparing 'stupid' with 'sstuuupiiid': 71%