如何实现PHP连接SQL Server数据库的类编写?
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本文共计395个文字,预计阅读时间需要2分钟。
php使用sqlsrv连接数据库,并检查连接是否成功:if (!($conn=sqlsrv_connect($this->server, array('UID'=> $this->userid, 'PWD'=> $this->password, 'Database'=> $this->database)))) { $this->error_log[]=sqlsrv_errors(); die();}
关闭数据库连接:sqlsrv_close($this->conn);
sqlsrv
conn = @sqlsrv_connect($this->server, array('UID' => $this->userid ,'PWD'=> $this->password, 'Database' => $this->database));
if($this->conn === false) {
$this->error_log[] = sqlsrv_errors();
die();
}
}
function close(){
sqlsrv_close($this->conn);
}
//query source
function query($sql,$params=array(),$open_close=1){
if($open_close){
$this->open();
}
$array=array();
for($i=0;$i
本文共计395个文字,预计阅读时间需要2分钟。
php使用sqlsrv连接数据库,并检查连接是否成功:if (!($conn=sqlsrv_connect($this->server, array('UID'=> $this->userid, 'PWD'=> $this->password, 'Database'=> $this->database)))) { $this->error_log[]=sqlsrv_errors(); die();}
关闭数据库连接:sqlsrv_close($this->conn);
sqlsrv
conn = @sqlsrv_connect($this->server, array('UID' => $this->userid ,'PWD'=> $this->password, 'Database' => $this->database));
if($this->conn === false) {
$this->error_log[] = sqlsrv_errors();
die();
}
}
function close(){
sqlsrv_close($this->conn);
}
//query source
function query($sql,$params=array(),$open_close=1){
if($open_close){
$this->open();
}
$array=array();
for($i=0;$i

