如何构建基于gradle的依赖关系逻辑?

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2026-10-12 11:21:08
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本文共计116个文字,预计阅读时间需要1分钟。

如何构建基于gradle的依赖关系逻辑?

在`dependency_logic.txt`文件中,以下是对给定内容的简化修改:

如何构建基于gradle的依赖关系逻辑?

plaintextOverride void apply(Project project) { if (project.name.matches([a-z]*-service)) { println(Skipping dependency management plugin for ${project.name}) return } else { println(Added dependency management plugin for ${project.name}) }}

dependency logic.txt

@Override void apply(Project project) { if(project.name.matches("[a-z]*-service")){ println("Skipping dependency managament plugin for ${project.name}") return }else { println("Added dependency managament plugin for ${project.name}") DependencyManagementPlugin dependencyManagementPlugin = new DependencyManagementPlugin() dependencyManagementPlugin.apply(project) } project.extensions.configure(DependencyManagementExtension, new ClosureBackedAction ({ imports { mavenBom("org.springframework.cloud:spring-cloud-dependencies:Brixton.BUILD-SNAPSHOT") } })) }

本文共计116个文字,预计阅读时间需要1分钟。

如何构建基于gradle的依赖关系逻辑?

在`dependency_logic.txt`文件中,以下是对给定内容的简化修改:

如何构建基于gradle的依赖关系逻辑?

plaintextOverride void apply(Project project) { if (project.name.matches([a-z]*-service)) { println(Skipping dependency management plugin for ${project.name}) return } else { println(Added dependency management plugin for ${project.name}) }}

dependency logic.txt

@Override void apply(Project project) { if(project.name.matches("[a-z]*-service")){ println("Skipping dependency managament plugin for ${project.name}") return }else { println("Added dependency managament plugin for ${project.name}") DependencyManagementPlugin dependencyManagementPlugin = new DependencyManagementPlugin() dependencyManagementPlugin.apply(project) } project.extensions.configure(DependencyManagementExtension, new ClosureBackedAction ({ imports { mavenBom("org.springframework.cloud:spring-cloud-dependencies:Brixton.BUILD-SNAPSHOT") } })) }